Question

Evaluate :${(x+3)}^3$

Answer 1

We have ${(a+b)}^3=a^3+b^3+3ab(a+b)$

$a=x,b=3$

${(x+3)}^3=x^3+3^3+3\times x\times 3(x+3)$

$=x^3+27+9x(x+3)$

$=x^3+27+9x^2+27x$