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Question

Evaluate:
limn[1+12+122+.....+12n]

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Solution

Now,
limn[1+12+122+.....+12n]
=limn⎢ ⎢ ⎢ ⎢112n+1112⎥ ⎥ ⎥ ⎥
=112 [ Since limn(12n+1)=0
=2.

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