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Byju's Answer
Standard XII
Mathematics
Limit
Evaluate : l...
Question
Evaluate :
lim
x
→
0
x
ln
(
1
+
2
tan
x
)
1
−
cos
x
Open in App
Solution
lim
x
→
0
x
ln
(
1
+
2
tan
x
)
1
−
cos
x
=
lim
x
→
0
x
ln
(
1
+
2
tan
x
)
(
1
−
cos
x
)
×
2
tan
x
×
2
tan
x
=
lim
x
→
0
x
×
2
tan
x
1
−
cos
x
=
lim
x
→
0
x
.2
.
tan
x
x
.
x
2
sin
2
x
2
=
lim
x
→
0
x
2
sin
2
x
2
=
lim
x
→
0
4
(
x
2
)
2
sin
2
x
2
=
4
.
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