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Byju's Answer
Standard XII
Chemistry
Stoichiometry
Evaluate: li...
Question
Evaluate:
lim
x
→
2
x
5
2
−
2
5
2
x
7
2
−
2
7
2
.
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Solution
Now,
lim
x
→
2
x
5
2
−
2
5
2
x
7
2
−
2
7
2
(
0
0
)
form.
Now applying L'Hospital's rule we get,
=
lim
x
→
2
5
2
×
x
3
2
7
2
×
x
5
2
=
5
7
×
1
2
=
5
14
.
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0
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