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Byju's Answer
Standard XII
Mathematics
Integration as Antiderivative
Evaluate li...
Question
Evaluate
lim
x
→
0
s
i
n
(
1
+
x
)
−
s
i
n
(
1
−
x
)
x
Open in App
Solution
lim
x
→
0
s
i
n
(
1
+
x
)
−
s
i
n
(
1
−
x
)
x
Using
s
i
n
C
−
s
i
n
D
=
2
s
i
n
(
C
−
D
2
)
c
o
s
(
C
+
D
2
)
lim
x
→
0
2
s
i
n
(
(
1
+
x
)
−
(
1
−
x
)
2
)
c
o
s
(
(
1
+
x
)
+
(
1
−
x
)
2
)
x
lim
x
→
0
2
c
o
s
1
s
i
n
x
x
=
2
c
o
s
1
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