Evaluate limx→0f(x), where f(x)={|x|x,x≠00,x=0
LHL=limx→0−f(x)
⇒limx→0−|x|x
as x→0−⇒x<0 slightly
⇒|x|=−x
limx→0−−xx=−1....(i)
and
RHL=limx→0+f(x)
⇒limx→0+|x|x
as x→0+⇒x>0+ slightly
⇒|x|=x
limx→0+xx=−1....(ii)
So, LHL≠RHL
∴limx→0f(x) does not exist.