wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate limx1x2+xlogexlogex1(x21)

Open in App
Solution

limx1x2+logexlogex1x21
limx1(x21)+logex(x1)x21
=limx1(1+logex(x+1))
1+limx1logex(x+1)(loge1=0)
=1+0
=[1].

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorisation and Rationalisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon