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Question

Evaluate limx1x2+xlogexlogex1(x21)

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Solution

limx1x2+logexlogex1x21
limx1(x21)+logex(x1)x21
=limx1(1+logex(x+1))
1+limx1logex(x+1)(loge1=0)
=1+0
=[1].

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