Evaluate - limx- 2 -x2-5x-6x2-3x-2-

x^2 5x+6=(x 3)(x 2) x^2 3x+2=(x 1)(x 2) Therefore, lim_x→ 2 [(x 3)(x 2)(x 1)(x 2)] =lim_x → 2x 3x 1=2 32 1= 1 ...

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Expansions to Remove Indeterminate Form

Evaluate : l...

Question

Evaluate :
$l i m_{x \to 2} [\frac{x^{2} - 5 x + 6}{x^{2} - 3 x + 2}]$

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