wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate: limxπsin2x+cos2xsin2xcos2x

Open in App
Solution

limxπsin2x+cos2xsin2xcos2x substituting for numerator and denominator, the above equation takes the form,
limxπ1cos2x, where cos2x=cos2xsin2x
=1cos2π=1





flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebra of Limits
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon