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Question

Evaluate:
limxπ3sin(π3x)2cosx1

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Solution

limxπ3sin(π3x)2cosx1

Let x=π3+t

limt0sin(π3π3t)2cos(π3+t)1

=limt0sint2[cos(t+π3]1

=limt0sint2[12cost32sint]1

=limt0sintcost3sint1

=limt0+sint3sint+1cost

=limt02sint2cost23×2sint2cost2+2sin2t2

=limt02sint2(cost2)2sint2(3cost2+sint2)

=limt0cost23cost2+sint2

13+0=13.

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