Question

Evaluate: $\int {\sec }^2\left(7-4x\right)dx$

Answer 1

$$\begin{gathered} \int {\sec }^2\left(7-4x\right)dx \\ =\frac{\tan \left(7-4x\right)}{-4}+C\mathit{}\mathit{}\mathit{}\mathit{}\mathit{}\mathit{}\mathit{}\mathit{}\left(\mathit{\because }\int {\sec }^{\mathit{2}\mathit{}}x\mathit{=}\tan \mathit{}x+C\right) \end{gathered}$$