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Question

Evaluate:
sin1{sinx+cosx2},π4<x<π4.

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Solution

sin1{sinxcosx2}
sin1{sinx2+cosx2}
sin1{cosπ4sinx+sinπ4cosx} [sinπ4=cosπ4=12]
sin1{sin(x+π4)} [sin(a+b)=sinacosb+sinbcosa]
x+π4 [sin1(sinx)=x]

1118961_1201107_ans_cf07d29a67a147d39e3c0d6e32c40cf5.jpg

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