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Question

Evaluate : sin290.cos245+4tan230+12sin2a2cos290+124

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Solution

Consider the given expression.

sin2900cos2450+4tan230+12sin2a2cos2900+124


Put the value of all trigonometry function in given expression, we get

sin2900cos2450+4tan230+12sin2a2cos2900+124

(1)2.(12)2+4.(13)2+12sin2a2(0)2+124

12+43+12sin2a+124

12sin2a+12+32+1224

12sin2a+5624

12sin2a+73


Hence, this is the answer.


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