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Question

Evaluate:
sin237120cos267120

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Solution

sin2xcos2B=cos(A+B)cos(AB)
So,
sin2x12cos26712
=cos(3712+6712)cos(37126712)
=cos(105)cos(30)

cos(x)=cosx
=cos(105)cos(30)
=cos(90+15)cos(30)
=+sin(15)cos(30)

sin15=624 , cos(30)=32

sin23712cos26712 =(624) (32)

=1868

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