Evaluate $s i n 29^{o} - c o s 61^{o}$

Open in App

Solution

$s i n 29^{o} - c o s 61^{o}$
$= s i n (90^{o} - 61^{o}) - c o s 61^{o}$
$= c o s 61^{o} - c o s 61^{o}$
$= 0$

Suggest Corrections

Similar questions

cos 61^{o}

{sin}^{2} 9^{o} + {sin}^{2} 18^{o} + . . . . . + {sin}^{2} 90^{o}

Evaluate : $\int \frac{x^{3}}{(x - 1) (x^{2} + 1)} d x .$

Evaluate $\int \frac{s i n x - x c o s x}{x (x + s i n x)}$ dx.

Evaluate : $\int_{0}^{π} \frac{x t a n x}{s e c x + t a n x} d x .$ OR Evaluate : $\int_{1}^{4} {|x-1|+|x-2|+|x-4|}dx.$

Join BYJU'S Learning Program