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Byju's Answer
Standard XII
Mathematics
General Solution of Trigonometric Equation
Evaluate : s...
Question
Evaluate
:
sin
(
2
cos
−
1
(
−
3
5
)
)
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Solution
sin
(
2
cos
−
1
(
3
5
)
)
cos
−
1
3
5
=
sin
−
1
4
5
2
sin
−
1
x
=
sin
−
1
x
√
1
−
x
2
2
sin
−
1
(
4
5
)
=
sin
−
1
[
−
4
5
×
3
5
]
=
sin
−
1
(
−
12
25
)
sin
(
2
cos
−
1
(
−
3
5
)
)
=
sin
(
sin
−
1
(
−
12
25
)
)
=
−
12
25
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