Evaluate sin-cos-2-1-2sin-cos-

According to question, (sinθ cosθ)^2=1 2sinθ.cosθ LHS, #160; =sin^2θ+cos^2θ 2sinθ. cosθ #160; =1 2sinθ .cosθ = RHSHence proved. ...

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Trigonometric Identities

Evaluate sin...

Question

Evaluate
$(sin θ - cos θ)^{2} = 1 - 2 sin θ . cos θ$

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Solution

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