Question

Evaluate $\sqrt{0.8}$ correct up to two places of decimal.

Answer 1

Let, $x=\sqrt{0.8}=\sqrt{\frac{8}{10}}=\sqrt{\frac{4\times 2}{10}\times \frac{10}{10}}=\frac{2}{10}\sqrt{20}=\frac{4}{10}\sqrt{5}=0.4\times \sqrt{5}$

$\therefore x=0.4\times 2.236$

$=0.8944$

$=0.89$