Question

Evaluate: $\sqrt[3]{327\times 64}$.

Answer 1

On prime factorisation of the numbers individually, we get,

$27=\underset{–}{3\times 3\times 3}=3^3$.

$64=\underset{–}{2\times 2\times 2}\times \underset{–}{2\times 2\times 2}=4^3$.

Therefore,

$\sqrt[3]{327\times 64}$ $=\sqrt[3]{33^3\times 4^3}=3\times 4=12$.

Hence, $12$ is the solution.