Question

Evaluate $\sqrt[3]{372.3}$, if $\log 0.72=\overline{1}.8591$

Answer 1

Let $x=\sqrt[3]{372.3}$. Then
$\log x={\left(72.3\right)}^{1/3}$

or $\log x=\frac{1}{3}\log 72.3$
or $\log x=\frac{1}{3}\times 1.8591$

$\Rightarrow \log x=0.6197$
or $x=\text{antilog}\left(0.6197\right)$
$=4.166$ (using antilog table)
Ans: 4.166