Evaluate- -a2-2ab-b2a2-2ab-b2

The correct option is A |a+ba b| √(a^2+2ab+b^2a^2 2ab+b^2) = √((a+b)^2(a b)^2) = |a+ba b| ...

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Byju's Answer

Standard VIII

Mathematics

Factors of Natural Numbers

Evaluate: √...

Question

Evaluate: $\sqrt{\frac{a^{2} + 2 a b + b^{2}}{a^{2} - 2 a b + b^{2}}}$

∣ ∣ ∣ \frac{a + b}{a - b} ∣ ∣ ∣

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\frac{a + b}{a - b}

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∣ ∣ ∣ \frac{a - b}{a + b} ∣ ∣ ∣

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(\frac{a + b}{a - b})^{2}

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Solution

The correct option is A $∣ ∣ ∣ \frac{a + b}{a - b} ∣ ∣ ∣$
$\sqrt{\frac{a^{2} + 2 a b + b^{2}}{a^{2} - 2 a b + b^{2}}}$
$=$ $\sqrt{\frac{(a + b)^{2}}{(a - b)^{2}}}$
$=$ $∣ ∣ ∣ \frac{a + b}{a - b} ∣ ∣ ∣$

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Similar questions

Simplify $\frac{a - b}{a} + \frac{a + b}{b}$

Find:
$(a + b + c) \times (a + b - c) =$

Which of the following is correct?
a) $(a - b)^{2} = a^{2} + 2 a b - b^{2}$
b) $(a - b)^{2} = a^{2} - 2 a b + b^{2}$
c) $(a - b)^{2} = a^{2} - b^{2}$
d) $(a + b)^{2} = a^{2} + 2 a b - b^{2}$

Q. More than One Answer Type
एक से अधिक उत्तर प्रकार के प्रश्न

If a – b = a² + b² + 2ab and a + b = a² + b² – 2ab, then which of the following is/are correct?

यदि a – b = a² + b² + 2ab तथा a + b = a² + b² – 2ab, तब निम्नलिखित में से कौनसा/कौनसे विकल्प सही है/हैं?

(a - b) \times (a^{2} + 2 a b + b^{2})

= ______

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Evaluate: √a2+2ab+b2a2−2ab+b2

The correct option is A ∣∣∣a+ba−b∣∣∣√a2+2ab+b2a2−2ab+b2= √(a+b)2(a−b)2= ∣∣∣a+ba−b∣∣∣

Evaluate: $\sqrt{\frac{a^{2} + 2 a b + b^{2}}{a^{2} - 2 a b + b^{2}}}$

The correct option is A $∣ ∣ ∣ \frac{a + b}{a - b} ∣ ∣ ∣$
$\sqrt{\frac{a^{2} + 2 a b + b^{2}}{a^{2} - 2 a b + b^{2}}}$
$=$ $\sqrt{\frac{(a + b)^{2}}{(a - b)^{2}}}$
$=$ $∣ ∣ ∣ \frac{a + b}{a - b} ∣ ∣ ∣$