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Question

Evaluate the (99)3 using suitable identities.

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Solution

We have,

(99)3

=(1001)3

We know that

(ab)3=a3b33ab(ab)

Therefore,

=(100)3133×100×1×(1001)

=10000001300(1001)

=1000000130000+300

=970299

Hence, this is the answer.


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