We have,
(99)3
=(100−1)3
We know that
(a−b)3=a3−b3−3ab(a−b)
Therefore,
=(100)3−13−3×100×1×(100−1)
=1000000−1−300(100−1)
=1000000−1−30000+300
=970299
Hence, this is the answer.
Evaluate the following using suitable identities: (99)3