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Question

Evaluate the below expression using identities:
(b7)2

A
b214b+49
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B
b2+14b+49
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C
b2+4914b
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D
b214b49
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Solution

The correct options are
A b214b+49
C b2+4914b
(b7)2=(b)22×b×7+(7)2
[Using identity(ab)2=a22ab+b2]
=b214b+49






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