Question

Evaluate the definite integral:

${\int }_1^2\frac{1}{x}dx$

• A. $\log 3$
• B. $\log 4$
• C. $\log 5$
• D. $\log 2$

Answer 1

The correct option is D $\log 2$

${\int }_1^2\frac{1}{x}dx$

$={\left[\log x\right]}_1^2$.........$(\because \int \frac{dx}{x}=\log x)$

$=\log 2-\log 1=\log 2$