Question

Evaluate the definite integrals :

${\int }_0^{\pi /2}\left(1+\cos x\right)dx$

• A. $\frac{\pi }{2}$
• B. $\frac{\pi }{2}+1$
• C. $\frac{\pi }{2}+2$
• D. $\pi$

Answer 1

The correct option is B $\frac{\pi }{2}+1$

${\int }_0^{\pi /2}1+\cos xdx$

$={[x+\sin x]}_0^{\pi /2}$

$=\frac{\pi }{2}+1-0-0$

$=\frac{\pi }{2}+1$