CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the definite integrals.
π40(2sec2x+x3+2)dx

Open in App
Solution

π40(2sec2x+x3+2)dx=2π40sec2xdx+π40x3dx+2π401dx=2[tanx]π40+14[x4]π40+2[x]π40=2tanπ4+14(π4)4+2(π4)=2+π2+π41024


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 5
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon