wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the definite integrals.
π0(sin2x2cos2x2)dx.

Open in App
Solution

π0(sin2x2cos2x2)dx=π0(cos2x2sin2x2)dx=π0cosxdx [cos2x=cos2xsin2x]=[sinx]π0=[sinπsin0]=0


flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Finite and Infinite Set
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon