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Byju's Answer
Standard XII
Mathematics
Skew Symmetric Matrix
Evaluate the ...
Question
Evaluate the determinant
Δ
=
∣
∣ ∣
∣
1
2
4
−
1
3
0
4
1
0
∣
∣ ∣
∣
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Solution
Δ
=
∣
∣ ∣
∣
1
2
4
−
1
3
0
4
1
0
∣
∣ ∣
∣
=
1
∣
∣
∣
3
0
1
0
∣
∣
∣
−
2
∣
∣
∣
−
1
0
4
0
∣
∣
∣
+
4
∣
∣
∣
−
1
3
4
1
∣
∣
∣
=
1
(
3
(
0
)
−
1
(
0
)
)
−
2
(
−
1
(
0
)
−
4
(
0
)
+
4
(
−
1
(
1
)
−
4
(
3
)
)
=
1
(
0
)
−
2
(
0
)
+
4
(
−
1
−
12
)
=
4
(
−
13
)
=
−
52
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25
Similar questions
Q.
The value of
Δ
=
∣
∣ ∣
∣
1
2
4
−
1
3
0
4
1
0
∣
∣ ∣
∣
is
Q.
The value of the determinant
⎛
⎜
⎝
1
2
4
−
1
3
0
4
1
0
∣
∣ ∣
∣
will be
.