Question

Evaluate the following:
$2sin{30}^{\circ }+3cos{60}^{\circ }–3tan{45}^{\circ }$

• A. 2
• B. $\frac{3}{2}$
• C. $\frac{1}{2}$
• D. $-\frac{1}{2}$

Answer 1

The correct option is D

$-\frac{1}{2}$

Evaluate the following:
$2sin{30}^{\circ }+3cos{60}^{\circ }–3tan{45}^{\circ }$
= $2\left(\frac{1}{2}\right)+3\left(\frac{1}{2}\right)–3\left(1\right)$
= $1+\frac{3}{2}–3$
= $-\frac{1}{2}$