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Question

Evaluate the following :
∣ ∣x+λxxxx+λxxxx+λ∣ ∣

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Solution

Let Δ=∣ ∣x+λxxxx+λxxxx+λ∣ ∣.

Applying C1C1+C2+C3, we get

∣ ∣3x+λxx3x+λx+λx3x+λxx+λ∣ ∣=(3x+λ)∣ ∣1xx1x+λx1xx+λ∣ ∣ [Taking (3x+λ) common from C1]

Δ=(3x+λ)∣ ∣1xx0λ000λ∣ ∣ [Applying R2R2R1,R3R3R1]

Δ=(3x+λ)λ00λ [Expanding along C1]

Δ=λ2(3x+λ)


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