Question

evaluate the following :
log_1/8 64

Answer 1

Dear Student,

$$\begin{gathered} {\log }_{\frac{1}{8}}64=\frac{\log 64}{\log {\displaystyle \frac{1}{8}}} \\ =\frac{\log 8^2}{\log 1-\log 8}=\frac{2\log 8}{0-\log 8} \\ =-2\mathrm{ANS}... \end{gathered}$$