Question

Evaluate the following by using the identities:
${92}^2$

Answer 1

We know $(a-b{)}^2=a^2+b^2-2ab$

By using this identity

${92}^2=(100-8{)}^2$

$={100}^2+8^2-2\times 100\times 8$

$=10000+64-1600$

$=8464$