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Question

Evaluate the following :
(cos0+sin45+sin30)(sin90cos45+cos60)

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Solution

(cos0+sin45+sin30)(sin90cos45+cos60)

=(1+12+12)(112+12)

=((1+12)+12)((1+12)12)

=(32+12)(3212)

We know that,
(a+b)(ab)=a2b2

Therefore,
(32+12)(3212)

=(32)2(12)2

=9412

=94(12×22)

=9424

=74

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