wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the following definite integral :
π/20 cos5xsin5x+cos5xdx

Open in App
Solution

Consider the given integral.

I=π/20cos5xsin5x+cos5xdx ……. (1)

We know that

baf(x)dx=baf(a+bx)dx

Therefore,

I=π/20sin5xcos5x+sin5xdx ……. (2)

On adding equation (1) and (2), we get

I=π/20sin5x+cos5xcos5x+sin5xdx

I=π/201dx

I=[x]π/20

I=π20

I=π2

Hence, this is the answer.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Property 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon