Consider the given integral.
I=∫π/20cos5xsin5x+cos5xdx ……. (1)
We know that
∫baf(x)dx=∫baf(a+b−x)dx
Therefore,
I=∫π/20sin5xcos5x+sin5xdx ……. (2)
On adding equation (1) and (2), we get
I=∫π/20sin5x+cos5xcos5x+sin5xdx
I=∫π/201dx
I=[x]π/20
I=π2−0
I=π2
Hence, this is the answer.