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Question

Evaluate the following definite integral :
π/20 cos5xsin5x+cos5xdx

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Solution

Consider the given integral.

I=π/20cos5xsin5x+cos5xdx ……. (1)

We know that

baf(x)dx=baf(a+bx)dx

Therefore,

I=π/20sin5xcos5x+sin5xdx ……. (2)

On adding equation (1) and (2), we get

I=π/20sin5x+cos5xcos5x+sin5xdx

I=π/201dx

I=[x]π/20

I=π20

I=π2

Hence, this is the answer.


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