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Question

Evaluate the following definite integrals as limit of sums.
40(x+e2x)dx

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Solution

40(x+e2x)dx40xdx+40e2xdx12[x2]40+12[e2x]40+c12×16=12[e81]+c8+12[e81]+c.

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Definite Integral as Limit of Sum
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