Question

Evaluate the following determinant :
$\left|\begin{array}{ccc}102& 18& 36\\ 1& 3& 4\\ 17& 3& 6\end{array}\right|$

Answer 1

$\left|\begin{array}{ccc}102& 18& 36\\ 1& 3& 4\\ 17& 3& 6\end{array}\right|$

Expanding the determinant, we get

$=\left(102\right(18-12)-18(6-68)+36(3-51\left)\right)$

$=102\left(6\right)-18(-62)+36(-48)$

$=612+1116-1728$

$=0$