Question

Evaluate the following :
$\frac{cosec{32}^{\circ }}{sec{58}^{\circ }}$

Answer 1

We have,
$\frac{cosec{32}^{\circ }}{sec{58}^{\circ }}=\frac{cosec({90}^{\circ }-{58}^{\circ })}{sec{58}^{\circ }}=\frac{sec{58}^{\circ }}{sec{58}^{\circ }}=1$

$[\because cosec({90}^{\circ }-\theta )=sec\theta ]$