Question

Evaluate the following integral:

${\int }_0^{\pi }1+\sin xdx$

• A. $\pi +2$
• B. $\pi /2$
• C. $\pi -2$
• D. None of the above

Answer 1

The correct option is A $\pi +2$

${\int }_0^{\pi }1+\sin xdx$

$={x-\cos x|}_0^{\pi }$

$=[\pi -(-1\left)\right]-[0-1]$

$=\pi +2$