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Question

Evaluate the following integral:
dxx+1x

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Solution


Given dxx+1x

=1x+1x ×x+1+xx+1+xdx

=x+1+xx+1xdx

=x+1+xdx

By using xndx=xn+1n+1+c

=23(x+1)3/2+23x3/2+c

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