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Question

Evaluate the following integrals:
02x2-3x+2 dx

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Solution

02x2-3x+2 dxWe know that, x2-3x+2=-x2-3x+2, x-1x-20 or, 1x2x2-3x+2, x2-3x+20 or, x-, 12, I=02x2-3x+2 dxI=01x2-3x+2 dx-12x2-3x+2 dxI=x33-3x22+2x01-x33-3x22+2x12I=13-32+2-83-6+4-13+32-2I=13-32+2-83+6-2+13-32I=1

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