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Question

Evaluate the following integrals:
-π/4π/4sin x dx

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Solution

-π4π4sin x dxWe know that, sin x=- sin x ,-π4 x0sin x, 0<xπ4I=-π4π4sin x dxI=-π40-sin x dx +0π4 sin x dxI=cos x-π40-cos x0-π4I=1-12-12+1I=2-22I=2-2

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