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Question

Evaluate the following integrals by expressing as a limit of sum.
(i) 21(2x+5)dx
(ii) 21x2dx
(iii) 21exdx

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Solution

(i)21(2x+5)dx=[x2+5x]214+10(1+5)=8(ii)21x2dx=[x33]21=8313=73(iii)21exdx=[ex]21=e2e

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