wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the following integrals : x2x4+x2+1dx

Open in App
Solution

We have,
I=x2x4+x2+1dx=dxx2+1+1x2=dx(x2+1x)21=12log⎜ ⎜ ⎜x+1x1x+1x+1⎟ ⎟ ⎟=12log(x2x+1x2+x+1)+C

Hence, this is the answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon