CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the following integrals:
e2xdx, xϵR

A
e3x3+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
e2x2+c
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
e4x4+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
e2x+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A e2x2+c
As we know that, axdx=axlna+c

we can write,
e2xdx=(e2)xdx=(e2)xlne2+c=e2x2lne+c=e2x2+c

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Standard Formulae 1
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon