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Question

Evaluate the following integrals:
e2xdx, xϵR

A
e3x3+c
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B
e2x2+c
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C
e4x4+c
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D
e2x+c
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Solution

The correct option is A e2x2+c
As we know that, axdx=axlna+c

we can write,
e2xdx=(e2)xdx=(e2)xlne2+c=e2x2lne+c=e2x2+c

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