wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the following limit:
limx0sin ax + bxax+sin bx,a,b,a+b0

Open in App
Solution

Here limx0sin ax+bxax+sin bx[00form]

Dividing numerator and denominator by ax,

limx0sin axax+bxaxaxax+sin bxax=limx0sin axax+bxaxaxax+sin bxbx×bxax

= 1+ba1+ba = 1.


flag
Suggest Corrections
thumbs-up
30
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Trigonometric Equations
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon