CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
6
You visited us 6 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the following limit:
limx0sin axsin bx,a,b0

Open in App
Solution

Here limx0sin axsin bx

= limx0[sin axax×ax×1sin bxbx×bx]

=limx0[sin axax×1sin bxbx×axbx]

=ablimx0[sin axax×1sin bxbx]

= ab×1×1=ab


flag
Suggest Corrections
thumbs-up
9
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
L'hospitals Rule
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon