wiz-icon
MyQuestionIcon
MyQuestionIcon
7
You visited us 7 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the following limit:
limx0 x sec x

Open in App
Solution

Here limx0 x sec x

= limx0×1cos x=limx0 xcos x=01=0.


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Quantum Numbers
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon