Question

Evaluate the following limits:

${lim}_{x\to -5}\frac{2x^2+9x-5}{x+5}$

Answer 1

${lim}_{x\to -5}\frac{2x^2+9x-5}{x+5}$

It is of the form $\frac{0}{0}$

$={lim}_{x\to -5}\frac{2x^2+10x-x-5}{x+5}$

$={lim}_{x\to -5}\frac{(x+5)(2x-1)}{(x+5)}$

$={lim}_{x\to -5}(2x-1)=2(-5)-1$

=10-1=-11