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Question

Evaluate the following limits:

limxπ1+cosxtan2x

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Solution

limxπ1+cosxtan2x

=limxπ[(1+cosx)sin2x×cos2x]

=limxπ[1+cosx1cos2x×cos2x]

=limxπ[1+cosx(1cosx)(1+cosx)×cos2x]

=limxπ[cos2 x(1cos x)]

=limxπ[cos2 π1cos π]

=(1)21(1)=12


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