wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Evaluate the following limits:

limxπ1+cosxtan2x

Open in App
Solution

limxπ1+cosxtan2x

=limxπ[(1+cosx)sin2x×cos2x]

=limxπ[1+cosx1cos2x×cos2x]

=limxπ[1+cosx(1cosx)(1+cosx)×cos2x]

=limxπ[cos2 x(1cos x)]

=limxπ[cos2 π1cos π]

=(1)21(1)=12


flag
Suggest Corrections
thumbs-up
72
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factorisation and Rationalisation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon