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Question

Evaluate the following :
sin230+sin245+sin260+sin290

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Solution

Given sin230+sin245+sin260+sin290

=(12)2+(12)2+(32)2+12 [sin45=12,sin60=32,sin30=12,sin90=1]

=14+12+34+1

=14+24+34+44

=1+2+3+44

=104=52

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